Perimeter of the floor of hall =2(l + b)
= 93750 \(\mathrm{cm}^{2}\)
NCERT has also published the … = 3000 + 4000 + 7500 = 14500 cm2 = 2(lh + bh + lb]
NCERT Book for Class 9 Maths Chapter 13 Surface Areas and Volumes is available for reading or download on this page. Otherwise you can also buy it easily online. = 2(225 + 75 + 168.75) \( \mathrm{cm}^{2}\)
The name of the chapter is a link to start online studying. (i) Edge of cube = 10 cm
Total surface area of cuboidal box - Total surface area of cubical box = 610 \(\mathrm{cm}^{2}\)
Cost of painting per \( m^{2}\) area = Rs 10
The external faces are to be polished and the inner faces are to be painted. Therefore, the height of the hall is 6 m. The paint in a certain container is sufficient to paint an area equal to 9.375 \( m^{2}\) . NCERT Solutions for Class 9 Maths Chapter 13 - Surface Areas and Volumes, curated by Vedantu equip students with all the necessary skills. Total surface area of cuboidal box - Total surface area of cubical box = 610 \(\mathrm{cm}^{2}\)
Ignoring the thickness of the plastic sheet, determine:
They ensure a smooth and easy knowledge of advanced concepts. Ans : Let length, breadth, and height of the rectangular hall be I m, b m, and h mrespectively. Free NCERT Books download for Class 9 Maths Chapter 13 - Surface Areas and Volumes on Vedantu.com. Cost of painting per \( m^{2}\) area = Rs 10
= 2(75 x 20)+ 2(100x 20)+ 75×100 However, it is given that the cost of painting the walls is Rs 15000. You can also watch the video solutions of NCERT Class9 Maths chapter 13 Surface area and volumes here. = (2 x 468.75) \( \mathrm{cm}^{2}\)
Surface area to be silver paint, Ex 13.9 Class 9 Maths Question 3. The name of the chapter is a link to start online studying. The diameter of a sphere is decreased by 25%. The floor of the room is not to be white-washed. Also please like, and share it with your friends! = 937.5 \( \mathrm{cm}^{2}\)
= 74 \( m^{2}\)
Lateral surface area of cuboidal box =2[lh+bh]
Length (j) of box = 12.5 cm
NCERT solutions provide a strong foundation for every chapter. =2lh+2bh+lb
Area of n bricks = (n x937.5) \( \mathrm{cm}^{2}\) = 937.5n \( \mathrm{cm}^{2}\)
Cost of painting 250h \( m^{2}\) area = Rs (250h x 10) = Rs 2500h
(30 + 24 + 20) \( m^{2}\)
Students can also download the NCERT Textbooks Solutions in PDF for Class 9 Maths. Chapter 14. =250 m
Cost of white-washlng 74 \( m^{2}\) area =Rs (74x7.50)
These solutions in maths for Class 9 is prepared considering the board and competitive examinations. Area to be white-washed = Area of walls + Area of ceiling of room
600\(\mathrm{cm}^{2}\) = 10 \(\mathrm{cm}^{2}\)
15000 = 2500h
Area of n bricks = (n x937.5) \( \mathrm{cm}^{2}\) = 937.5n \( \mathrm{cm}^{2}\)
Ans : (i) Edge of cube = 10 cm
=(1.95 + 1.625 + 1.875) m2 =5.45 \( m^{2}\)
=2( l + b )h
= 19100 x \(\frac { 20 }{ 100 }\) = ₹ 3820 (ii) Total surface area of cubical box =\( 6(\text { edge })^{2}\) =\( 6(10 \mathrm{cm})^{2}\)= 600 \(\mathrm{cm}^{2}\)
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Digital NCERT Books Class 9 Maths pdf are always handy to use when you do not have access to physical copy. 15000 = 2500h
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You can also check out NCERT Solutions of other classes here. Lateral surface area of cubical box - Lateral surface area of cuboidal box = 400 \(\mathrm{cm}^{2}\) - 360\(\mathrm{cm}^{2}\) = 40 \(\mathrm{cm}^{2}\)
(i) Box is to be open at top. Area to be white-washed = Area of walls + Area of ceiling of room
=2( l + b )h
Here you will find each and every chapter of class IX maths. surface area of the cuboidal box by 40\(\mathrm{cm}^{2}\)
Breadth (b) of box 1.25 m
Class 9 Maths Chapter 13 Exercise 13.4 - 9 Questions with Solutions in PDF. Length (l) of room = 5 m
The front compound wall of a house is decorated by wooden spheres of diameter 21 cm, placed on small supports as shown in figure. Comments Cancel reply. Surface Areas and Volumes Class 9 NCERT Book: If you are looking for the best books of Class 9 Maths then NCERT Books can be a great choice to begin your preparation. Therefore, the height of the hall is 6 m. Ans : Total surface area of one brick = 2(lb + bh + /h)
(30 + 24 + 20) \( m^{2}\)
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